![]() ![]() A three body force is one which is felt only when there are at least three particles present, for example, in a three-nucleon system such as a triton, the nucleus of tritium, or a He-3, made of two protons and one neutron, a two-body force acts between nucleons 1 and 2, between nucleons 2 and 3, and between nucleons 3 and 1. ![]() In nuclear physics, it is not possible to rule out completely three body and higher particle-rank terms in the nuclear interaction. So superposition is not necessarily obvious. This is independent from the fact that Coulomb's law describes a force. But, a vector has an algebraic structure. While Coulomb's law states the electric force between 2 charged particles, it seems obvious to use vectors. We use vectors because they are convenient in applying Coulomb's law. ![]() The individual charges are unaffected due to the presence of other charges. It would also be mathematically valid to say that at some point linear superposition no longer holds, so they need to cover everything in the statement.įorce on any charge due to a number of other charges is the vector sum of all the forces on that charge due to the other charges, taken one at a time. they are just being more general than the case of just two fields. The bold part just says that this type of thing doesn't happen for when there are $N$ or more fields present, i.e. It does seem like electric fields do just linearly superimpose (however, their energies do not). However, we don't see this type of thing. $$\mathbf E_$$įor some constant $k$ to make the unts work out. For example, there wouldn't be anything mathematically incorrect with saying that the new field due to two fields is given by You could imagine that there is an interaction between electric fields such that if two fields "overlap" then other things happen (like stronger fields, perhaps). Superposition of charges (or the electric field etc) is a physical assumption, not a mathematical one. ![]()
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